Attempt to get 3.5 RETURN_END_IF working

This feels hacky and I'm not sure is quite right.
Untili we understand better what to do though, we'll
go with it.

uncompyle6/parsers/parse3.py

@@ -603,11 +603,16 @@ class Python35onParser(Python3Parser):
                 WITH_CLEANUP_START WITH_CLEANUP_FINISH END_FINALLY
 
 
-        # Python 3.5+_ does jump optimization that scanner3.py's detect
-        # structure can't fully work out. So for now let's allow
-        # RETURN_END_IF the same as RETURN_VAL
+        # Python 3.5+ does jump optimization
+        # In <.3.5 the below is a JUMP_FORWARD to a JUMP_ABSOLUTE.
+        # in return_stmt, we will need the semantic actions in pysource.py
+        # to work out whether to dedent or not based on the presence of
+        # RETURN_END_IF vs RETURN_VALUE
+
+        ifelsestmtc ::= testexpr c_stmts_opt JUMP_FORWARD else_suitec
         return_stmt ::= ret_expr RETURN_END_IF
 
+
         # Python 3.3+ also has yield from. 3.5 does it
         # differently than 3.3, 3.4
 

uncompyle6/semantics/pysource.py

@@ -710,6 +710,11 @@ class SourceWalker(GenericASTTraversal, object):
             if self.return_none or node != AST('return_stmt', [AST('ret_expr', [NONE]), Token('RETURN_VALUE')]):
                 self.write(' ')
                 self.preorder(node[0])
+            # 3.5 does jump optimization. The RETURN_END_IF in the return
+            # statement means to dedent. Earlier versions will just have
+            # RETURN_VALUE
+            if self.version >= 3.5 and node[-1] == 'RETURN_END_IF':
+                self.indentLess()
             self.println()
             self.prune() # stop recursing