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if bug in lambda with ifelse

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A synergy of Python's irregular lambda, its custom ifelse syntax and its
marvelous indentation regime. Fixes #130
This commit is contained in:
rocky
2017-10-05 11:00:55 -04:00
parent 86305097d2
commit b3359439f9
9 changed files with 46 additions and 8 deletions
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11
uncompyle6/semantics/consts.py
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@@ -173,8 +173,13 @@ TABLE_DIRECT = {
'ret_cond': ( '%p if %p else %p', (2, 27), (0, 27), (-1, 27) ),
'conditionalnot': ( '%p if not %p else %p', (2, 27), (0, 22), (4, 27) ),
'ret_cond_not': ( '%p if not %p else %p', (2, 27), (0, 22), (-1, 27) ),
'conditional_lambda': ( '(%c if %c else %c)', 2, 0, 3),
'return_lambda': ('%c', 0),
'conditional_lambda': ( '%c if %c else %c', 2, 0, 4),
# The semicolon is because Python 3.x can have be dead code as a result of its
# optimization. We don't Python's remove dead code (yet) anymore than Python does.
# So without that we would have "return 2return3" rather than "return 2;return 3"
'return_lambda': ('return %c;', 0),
'compare': ( '%p %[-1]{pattr.replace("-", " ")} %p', (0, 19), (1, 19) ),
'cmp_list': ( '%p %p', (0, 29), (1, 30)),
'cmp_list1': ( '%[3]{pattr} %p %p', (0, 19), (-2, 19)),
@@ -209,6 +214,7 @@ TABLE_DIRECT = {
'raise_stmt3': ( '%|raise %c, %c, %c\n', 0, 1, 2),
# 'yield': ( 'yield %c', 0),
# 'return_stmt': ( '%|return %c\n', 0),
'return_if_stmt': ( 'return %c\n', 0),
'ifstmt': ( '%|if %c:\n%+%c%-', 0, 1 ),
'iflaststmt': ( '%|if %c:\n%+%c%-', 0, 1 ),
@@ -331,6 +337,7 @@ PRECEDENCE = {
'ret_or': 26,
'conditional': 28,
'conditional_lamdba': 28,
'conditionalnot': 28,
'ret_cond': 28,
'ret_cond_not': 28,